[C++] Honor string length in FindEndOfLine

When the character after the string is a backslash,
FindOfLine returned a wrong length.

1 files changed, 4 insertions, 0 deletions

diff --git a/strutil.cc b/strutil.cc
index 9d37052..d3c14d8 100644
--- a/strutil.cc
+++ b/strutil.cc
@@ -427,6 +427,10 @@ size_t FindEndOfLine(StringPiece s, size_t e, size_t* lf_cnt) {
   static const char ranges[] = "\0\0\n\n\\\\";
   while (e < s.size()) {
     e += SkipUntilSSE42(s.data() + e, s.size() - e, ranges, 6);
+    if (e >= s.size()) {
+      CHECK(s.size() == e);
+      break;
+    }
     char c = s[e];
     if (c == '\0')
       break;